6[2-(3+6x)]-4x=-8+2(1-20x)

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Solution for 6[2-(3+6x)]-4x=-8+2(1-20x) equation:


Simplifying
6[2 + -1(3 + 6x)] + -4x = -8 + 2(1 + -20x)
6[2 + (3 * -1 + 6x * -1)] + -4x = -8 + 2(1 + -20x)
6[2 + (-3 + -6x)] + -4x = -8 + 2(1 + -20x)

Combine like terms: 2 + -3 = -1
6[-1 + -6x] + -4x = -8 + 2(1 + -20x)
[-1 * 6 + -6x * 6] + -4x = -8 + 2(1 + -20x)
[-6 + -36x] + -4x = -8 + 2(1 + -20x)

Combine like terms: -36x + -4x = -40x
-6 + -40x = -8 + 2(1 + -20x)
-6 + -40x = -8 + (1 * 2 + -20x * 2)
-6 + -40x = -8 + (2 + -40x)

Combine like terms: -8 + 2 = -6
-6 + -40x = -6 + -40x

Add '6' to each side of the equation.
-6 + 6 + -40x = -6 + 6 + -40x

Combine like terms: -6 + 6 = 0
0 + -40x = -6 + 6 + -40x
-40x = -6 + 6 + -40x

Combine like terms: -6 + 6 = 0
-40x = 0 + -40x
-40x = -40x

Add '40x' to each side of the equation.
-40x + 40x = -40x + 40x

Combine like terms: -40x + 40x = 0
0 = -40x + 40x

Combine like terms: -40x + 40x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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